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All Numbers Are Equal 9 h& t' ], G% V
Theorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then |; ^; p' C1 Q( b M2 L) B
3 e$ i( G/ }# i% {) Ma + b = t' Z& A% r4 K, T7 Y9 u2 f
(a + b)(a - b) = t(a - b)
( d% s! j$ r8 Ia^2 - b^2 = ta - tb4 D& j5 ~4 b- b" C- i
a^2 - ta = b^2 - tb
, U- }$ j( |8 l2 R3 M" b& [a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/47 m( Y7 K# c7 O' O o) e
(a - t/2)^2 = (b - t/2)^2) {/ Z) m8 p+ R7 {8 @1 M+ m c$ I
a - t/2 = b - t/2
- v, k A7 w( k1 n* D% c* V# M7 s# wa = b
) M, R& U: A6 l1 a+ ?, H! _
# }/ {$ d! N- d. CSo all numbers are the same, and math is pointless. |
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发表于 2006-6-13 09:17
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