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All Numbers Are Equal
- Y& e' e* P4 q0 Z6 u( bTheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then : w* e' V! U$ _6 `
+ \. Z3 l( [0 X9 I9 i1 Qa + b = t1 D, h h! ^% T9 I- Q1 r' A
(a + b)(a - b) = t(a - b), U9 s) Z7 P0 z: w. g3 E
a^2 - b^2 = ta - tb. T5 C1 e+ o; p( B7 e) X* p
a^2 - ta = b^2 - tb4 e' Q# J& X: V7 |% O( m" u
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4; ]9 H0 f$ _4 ~
(a - t/2)^2 = (b - t/2)^2
# I! H- q0 r' f# o5 _0 J, R9 K, a" ^a - t/2 = b - t/2 A! T8 H; C' l$ l6 V w
a = b & x5 t; U& v- j+ w
8 A5 z0 e4 v: Q" VSo all numbers are the same, and math is pointless. |
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