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All Numbers Are Equal
! B. J! ^2 Q8 {9 Z3 J! a% s; h8 yTheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then 7 D2 z: c \+ t, K' O* u. A
2 F* `; ^4 g; W. g) b
a + b = t# j t! J# Q0 p2 X) r1 d2 A
(a + b)(a - b) = t(a - b)" d" Y5 f7 u6 [. b) s4 {
a^2 - b^2 = ta - tb
2 g! I5 n3 v; a; o |; t/ ka^2 - ta = b^2 - tb4 z$ [ w+ M1 }) ?9 j; s
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/40 e' k# Y" v5 g6 v E. X
(a - t/2)^2 = (b - t/2)^2; r+ s9 T( ~, B- i, n) Y* M
a - t/2 = b - t/2
5 {& l% R% j/ S. ua = b 5 u# F! g- B+ {6 b( j0 z g
3 g* X. S7 ]5 Y0 G7 t
So all numbers are the same, and math is pointless. |
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