求助一到地球物理的题

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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置
7 J3 t- H  _$ g7 x2 \, J
0 ~- g8 g# {5 y% ?4 D# N

6 s2 p& r5 s& G" w% p; [' y(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:
& J6 r, e/ v+ p' J( a" |
4 |, `8 h7 M; n3 r- N; Hmz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.

Calculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).
0 E& b2 A0 I, D  ~: E