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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置; S2 c o- K9 I5 |
! v" m5 [& h6 ~2 i3 ^2 U
/ b3 X8 l( s4 B$ e8 B8 x8 T9 r; d: m# c5 y
(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:
) g# b4 Y$ b9 q* v4 f9 K+ T W8 Y8 G4 }. c! u- ]9 Z# q
mz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.
% M) E! N4 m8 R1 d' t) C- }1 e1 C7 M( C# N# u
Calculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).8 q2 P w5 d7 M$ }: ]5 C
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发表于 2012-4-2 21:27
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