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Suppose Intr is annually compounded # W0 h) v& x; d' l- b6 G
Month 0 Mon. 8 Mon. 129 i7 x! y; R) A5 Y% m1 o; D
Cash Principal X -750 -950
6 x7 _, o1 t( x. x; J- `9 O) eCash Intr (Should Pay) -X*9.5%*8/12 -(X-750)*9.5%*4/12 & o/ R/ [% f. x* ?) S' P
PV at mon 0 X -[750+X*9.5%*8/12] -[950+(X-750)*9.5%*4/12]) I# O& ~+ V, \4 b
/(1+7.75%*8/12) /(1+7.75%*12/12)6 k& z+ ?" Y2 u; X! U
$ v4 A4 ~# f! A7 {
these 3 should add up to 0, i.e. NPV at month 0 is 0.# x5 c I2 e2 N# S3 ?% {# A# _
3 t% ?; ?& M" S9 E3 k5 n
Conclusion X = 1729.8 # {# K" q" U6 g C/ p
I0 U4 b7 ^; ~, P1 Y5 NSo, Initial borrowing was 1730 *(1+7.5%) 1859.5 approx. $1,860
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