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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 4 ^/ ^- R: O8 p
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1# jack_lai
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足球看完了来看看题目。9 |- L2 u0 Y6 r/ b/ E8 ~% W6 m- A3 J7 j
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The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
( j7 Z- o6 U: Y$ \3 k+ v/ IThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)9 m* L) Z- q9 i/ i& Y, M2 A1 D
We can see it is not easy to install the 22 meters heat trace according as figure 1* n5 g9 {0 j3 H5 m$ k% U! N b9 T4 w# f' F
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As a normal question we just discuss:! q( l4 ], U1 B$ ~: A
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? 5 o8 a% c+ x9 ?# s
I call this is JACK LAI Spiral Method 螺旋法 x5 b+ y' N) c* I* D I: X
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.+ n2 d. ^5 v) e, }+ `
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
7 `% `( _. o+ B; b( ]$ F2 c7 kBecause the pipe is horizontal, position 0 can not be placed. See figure 2& a4 `' R6 O) }7 W2 j" O$ _/ \; P! v
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
$ N' X) Q4 Q8 XThe total heat trace that can be installed here is about
! F) J O# k2 L2 m7 r) l9 O1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters1 m6 ]: B7 W! F2 @
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
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Note :
" k, a5 E1 f/ l- G4 n( s/ L1. The minimum bend radius:
; R7 ?% Y0 a+ b1 H' z' e1 GBecause the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is" C8 j( z( H' R$ ]
5/16 *6 = 30/16 almost = 2 inches2 O: S, U/ z; s* }% D2 C
So the maximum bend radius is 2 inches.
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Summary
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+ C, z5 r M+ v! C `! M I* q+ gFor 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
: G/ E9 N3 v) a/ k) oif the pipe is horizontal, The length of heat trace can be installed is about" O( R, u5 ?. J+ i$ l. Y- u1 V
1 * 9 = 9 meters# @! H1 g( x* _
If the pipe is vertical, The length of heat trace can be installed is about
9 u$ q9 l1 k1 b( I }1 u9 k1 * 10 = 10 meters.
; i7 v! z) W* N! FFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe e: s) u- D) k3 B# h0 n
if the pipe is horizontal , The length of heat trace can be installed is about
, o, m2 P" F# O o3 F4 t1 * 4 = 4 meters
4 q3 c A5 w* r& n- JIf the pipe is vertical, The length of heat trace can be installed is about% J% z8 p1 i: F) X; `/ t
1 * 5 = 5 meters. |
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