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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑
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足球看完了来看看题目。* K6 O7 ?0 F6 e* l, |8 J# v5 K7 A% e
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The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)! t9 i, H% B$ d. x
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
% x1 |3 V2 u" b& c, |& RWe can see it is not easy to install the 22 meters heat trace according as figure 14 A4 }% r3 Y" s$ L! I/ _
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As a normal question we just discuss:! ]3 n& g, N$ k- E
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ?
( x4 c: D5 G2 s9 g# W4 U% X- f! i( BI call this is JACK LAI Spiral Method 螺旋法
( B5 g$ _! w; ^+ p2 X1 ]% MThe outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
% C. B; d! |+ o! C' k7 u. uThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. % K5 U, q( s' P( U3 c
Because the pipe is horizontal, position 0 can not be placed. See figure 20 H4 v. Y0 v8 i. I& m
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3: j, b+ Q" Y3 z: ^ u
The total heat trace that can be installed here is about & S, W0 s' T' j$ C! j
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
8 @+ f7 j2 i& Y+ uSo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
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! @0 u, H( R ^9 h6 A1 oNote :" ]2 W1 G# X1 N, h) v J7 t: {. _7 u! a
1. The minimum bend radius:
% t3 |6 H; Z9 ~7 {1 ABecause the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
% z: d- n3 R! s6 n; Q5/16 *6 = 30/16 almost = 2 inches
9 K. d) W; c) QSo the maximum bend radius is 2 inches.
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Summary
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! A2 E" h% ]9 r% a& |. OFor 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe" A# E m! q0 I% m9 s8 W, ~* y8 l( m; m
if the pipe is horizontal, The length of heat trace can be installed is about
) z6 U3 M# \6 m- d) ~1 k1 * 9 = 9 meters
" J9 _, e7 \) n% YIf the pipe is vertical, The length of heat trace can be installed is about
& h4 F% U7 w- n1 * 10 = 10 meters.
$ T5 U8 s3 Y0 A: dFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe3 r4 m* q/ o4 }% x2 O- B$ J- Y
if the pipe is horizontal , The length of heat trace can be installed is about+ Z# i. k9 U/ m: X' I
1 * 4 = 4 meters
5 R. { J9 f, v, N& FIf the pipe is vertical, The length of heat trace can be installed is about
- O" I# J& ~* C# v3 v1 T4 h3 `1 * 5 = 5 meters. |
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