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All Numbers Are Equal
" v( \9 q5 b. v7 v* k' \" _; FTheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then * C- x) [8 j5 |2 F8 J7 W$ s
! z" G9 Q1 U1 d- ]# Ja + b = t0 u S8 C; u8 x0 B6 ~
(a + b)(a - b) = t(a - b)% H. w" V, {7 T# l7 G
a^2 - b^2 = ta - tb
" i" w; M$ j$ t# `; L, F- _) _! Qa^2 - ta = b^2 - tb
& o0 w$ A$ A, X6 a) E1 va^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4, U M# n# e8 V+ |2 f, ?3 h
(a - t/2)^2 = (b - t/2)^2+ N1 ]6 }1 P' P0 F& Y
a - t/2 = b - t/2+ N% ]0 f) j- y. N
a = b
% `. V- d" m* x' }6 e, e7 r$ b- c6 a' S+ e# r
So all numbers are the same, and math is pointless. |
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