All Numbers Are Equal % w" E0 h; x6 Y, @( ]
Theorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then ( A1 R* V- z9 e4 c
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a + b = t 3 |: f6 u( r. E7 S(a + b)(a - b) = t(a - b): B( ]0 I7 G/ y! q; \) @ r
a^2 - b^2 = ta - tb 8 g1 z) ?# F; {3 k3 @a^2 - ta = b^2 - tb4 C( N2 y8 \5 a* b& Y
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4 8 d/ t3 A; p9 h' X( Y2 i4 R0 a(a - t/2)^2 = (b - t/2)^2/ O5 D1 _" c& w L0 O
a - t/2 = b - t/2 8 f8 d U9 \ e/ f- na = b ' u" L6 I! T6 m& C7 ]+ ^- u : U. m; w4 c Y' `2 P- f: s0 k: LSo all numbers are the same, and math is pointless.