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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑
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4 V' W7 g' J+ X4 O, { 1# jack_lai ' e8 R/ y) @3 b9 r5 B# v+ x
* ~! k4 A* q4 [" h x! c足球看完了来看看题目。
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The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
/ G. D) a V; x) U# u/ r. f+ \1 GThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
4 t6 _# H$ Q$ y, Q7 E: L, vWe can see it is not easy to install the 22 meters heat trace according as figure 1' I, E C$ t( Z* Z" {1 E; Q/ h7 J
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# k, Z- a6 t, wAs a normal question we just discuss:
. L4 p* ~. B( Q+ }How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? 3 o2 `2 e# K7 l( B8 h k
I call this is JACK LAI Spiral Method 螺旋法" G" N/ G8 g* o3 U- v
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.% I5 j) C. w" ^
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. ) r, U1 I3 k3 `# h
Because the pipe is horizontal, position 0 can not be placed. See figure 24 |% f) n0 n9 y G* V( m
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
" u1 G# d" @! M* F7 Y4 f; sThe total heat trace that can be installed here is about
9 }5 i- \( @0 [& J1 W1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
# t) _2 u* U! R4 {' KSo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. 7 }7 s& I5 ]7 q$ K
7 P/ n, T4 H& Z0 {; z% lNote :
7 m: g# N: i' v8 X# x1. The minimum bend radius:$ Z# G9 }9 F5 l( t# r1 O; @2 z$ h
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
1 V$ m F' i+ [ O5/16 *6 = 30/16 almost = 2 inches1 n A3 i: v3 M
So the maximum bend radius is 2 inches.
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Summary
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6 H( D' v8 m1 ~. X ^. P" KFor 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
n! I1 G! Y a8 e% V- j& rif the pipe is horizontal, The length of heat trace can be installed is about
+ Y5 V' I4 j1 E; O1 * 9 = 9 meters) t% K5 I$ C2 A7 R
If the pipe is vertical, The length of heat trace can be installed is about
( v9 t5 e+ x0 b+ A0 G5 ]% T1 * 10 = 10 meters.
5 k* O$ \2 m- \1 s( W R; iFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe- v/ Y& R9 e, \" W4 ~
if the pipe is horizontal , The length of heat trace can be installed is about
" W$ b8 H. U0 L1 * 4 = 4 meters
1 K8 N* A1 \ q: [If the pipe is vertical, The length of heat trace can be installed is about \4 ~3 `+ |' q+ k J$ D
1 * 5 = 5 meters. |
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