 鲜花( 0)  鸡蛋( 0)
|

楼主 |
发表于 2010-7-10 17:18
|
显示全部楼层
本帖最后由 jack_lai 于 2010-7-10 18:52 编辑
. Z6 ? d! @3 U, z5 D
\2 m. h/ y8 i% ?: n+ x 1# jack_lai
) R7 I* u8 {$ Q+ ?/ w6 p$ {" E' n! _& }0 u% S
足球看完了来看看题目。
6 u" F0 V F) A9 J6 }3 c) d( P2 T. l* o* l9 \0 t
The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)" s& T, q% b, z2 R- \4 F' M% L
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
' _3 P+ ]" t! f) M) _8 G: i$ TWe can see it is not easy to install the 22 meters heat trace according as figure 10 o4 p; }' B* x/ k
0 @ x: {0 `; S# C; G. N1 G6 i
3 ~& T7 a) A0 H0 W+ J4 r
6 }+ |" z, B3 W
# {( {! {; g8 EAs a normal question we just discuss: _' E ]" y% F b; w R8 U4 o) R9 n
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ?
; u7 Z6 S+ J( P* j9 m6 [' d8 MI call this is JACK LAI Spiral Method 螺旋法 v& z/ g6 ~ s: m8 a: V
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2." y/ ?7 \$ G6 g* y
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
9 u2 i/ _) E0 O2 qBecause the pipe is horizontal, position 0 can not be placed. See figure 25 d2 n. t4 C2 C8 D
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
8 J d; Y N7 S: @7 k/ _0 VThe total heat trace that can be installed here is about * @2 X0 a7 c+ u; q1 {! ^
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
7 b- U! f U8 D+ eSo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
$ D4 _& Z v3 b2 [! @* w# }8 w7 e; ]$ d& O# w
Note :3 \- C- s6 a2 D9 l
1. The minimum bend radius:
% J; G: _$ A9 q; }0 H& |Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is- u6 V, v, ^3 k, C8 w4 u
5/16 *6 = 30/16 almost = 2 inches3 b3 Q3 W/ i" c& ]* ]8 e
So the maximum bend radius is 2 inches.+ I8 Z. m) H6 w! ^$ i2 [* B
8 e: b9 A8 {) @8 o& V+ J' S% N* t
4 n9 L* \% C A) n2 F
4 I. @0 P5 N1 L' x& x+ U- JSummary9 j( H, v( D8 J; T; B& A& X
As regular , I2 E. l, s3 q1 X) P! ]
For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe/ [8 o- ~+ ~) h& V
if the pipe is horizontal, The length of heat trace can be installed is about0 m% Y: k& h% K z3 ~6 T
1 * 9 = 9 meters$ q% X# i- |- i! F; x5 {& T
If the pipe is vertical, The length of heat trace can be installed is about$ u! z B# f7 u! O- Q
1 * 10 = 10 meters.
0 ^( a$ B$ Q% Q& F$ D/ v7 K# YFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
1 u$ a0 X( ]% X2 I X" H4 iif the pipe is horizontal , The length of heat trace can be installed is about
# e. ^& a8 y U1 * 4 = 4 meters# p( t3 z) I3 I8 |7 _3 s
If the pipe is vertical, The length of heat trace can be installed is about
! N# x+ K3 Y3 o1 * 5 = 5 meters. |
|