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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 7 y3 |5 k4 _& i0 _* o
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足球看完了来看看题目。
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The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)( ^. ^! Y; E/ v) g2 v! _
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
3 W/ P+ {% J! L/ A" ~' VWe can see it is not easy to install the 22 meters heat trace according as figure 1
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As a normal question we just discuss:3 q. o" O8 Q, O- E: Q
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ?
0 R5 i2 J* n4 k* r( _I call this is JACK LAI Spiral Method 螺旋法
+ q2 N0 `# a2 ~2 W/ D$ p M. o# IThe outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
# F/ N/ q, ~2 I+ Z8 nThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
. U5 v# i4 v c3 ?Because the pipe is horizontal, position 0 can not be placed. See figure 2# b7 z: p. |) D+ A% h- Y, G) ?
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3, Q/ K* k1 c. r0 x4 ~: a
The total heat trace that can be installed here is about 0 G9 U; Y P; I1 t4 z
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters$ x) x3 @: c" ]/ L* k. G
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. 9 W% a$ m5 X _1 D$ y; A
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1. The minimum bend radius:
( [* [5 ?! x0 j& x: U* eBecause the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
: Y3 v" i9 o$ m+ |5/16 *6 = 30/16 almost = 2 inches0 ?* O# C% N2 E" o; Y
So the maximum bend radius is 2 inches.
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Summary
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For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe" s- k# e. B+ E( x* u
if the pipe is horizontal, The length of heat trace can be installed is about9 }8 o: x1 j/ ^& u \/ G
1 * 9 = 9 meters
9 s. \4 v( o/ l- f' RIf the pipe is vertical, The length of heat trace can be installed is about4 M$ g- {: L5 h0 l# w. U% Z
1 * 10 = 10 meters. ' d6 ^6 \" y `8 X0 d+ ]
For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe8 I+ Y; |% l2 p }$ r- A
if the pipe is horizontal , The length of heat trace can be installed is about% c% u; x6 z& ]& q# @0 S0 ?7 y
1 * 4 = 4 meters
3 y Q- y5 s a( A" F6 J/ p f" sIf the pipe is vertical, The length of heat trace can be installed is about
$ W9 o6 x0 s8 @/ l& |0 Q1 * 5 = 5 meters. |
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