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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 3 g8 }' \' s8 N$ o c( W
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1# jack_lai
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足球看完了来看看题目。1 n+ ^; P0 `% e0 a
2 d2 h; m* ~- Z- d% ~3 sThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)0 t) A: o+ O7 [1 z! ?) K' j
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
3 d2 \8 z( T' G. RWe can see it is not easy to install the 22 meters heat trace according as figure 17 X4 P. l$ X& O
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P8 u, v0 _, Y( s% \: rAs a normal question we just discuss:# F% z% A1 [& |7 w
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? 3 D% r% `$ Z$ s
I call this is JACK LAI Spiral Method 螺旋法
% n4 t+ E3 e$ B) G6 ]2 R6 S7 RThe outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
/ ]* F- }9 I% h# V& m" KThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
4 P! n$ g" m4 R# u& UBecause the pipe is horizontal, position 0 can not be placed. See figure 2: Z+ G1 Z2 d# {% M2 X4 z
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
9 }; ~4 F1 g c: jThe total heat trace that can be installed here is about * Q$ w1 c" K0 Q4 y' e" b, N' `
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters; I- U( x3 C: \" H0 t5 m6 }2 x& m
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. * L/ Z: O% q+ _4 U
3 x9 o. R) s$ k1 g" f+ JNote :
5 G2 I3 J% P0 X9 s1. The minimum bend radius:
$ V @/ S3 T4 c0 NBecause the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
! U: C% C8 ~0 D8 b! p5/16 *6 = 30/16 almost = 2 inches
( g: F( B1 f7 J3 z) |So the maximum bend radius is 2 inches.' T. _' O3 `+ f& t6 m" ^* y) J. W
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Summary
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For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe9 ]( H3 V0 `' Y' V; `- A
if the pipe is horizontal, The length of heat trace can be installed is about
0 g7 K6 Y9 t9 d* Z8 n5 c. b3 d5 G1 * 9 = 9 meters; k* s8 A' T/ s$ T" D `
If the pipe is vertical, The length of heat trace can be installed is about
. T: V1 x9 |/ A; [1 * 10 = 10 meters.
# f& e6 n) @( ]% ?: Y4 ]; UFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe8 B7 b% a. N X0 L5 A( D5 }
if the pipe is horizontal , The length of heat trace can be installed is about
2 e, r) J2 h" M" T8 L9 e( r7 ~1 * 4 = 4 meters
; S! j6 H( @4 j" FIf the pipe is vertical, The length of heat trace can be installed is about
. M, @. O1 A5 a: n1 * 5 = 5 meters. |
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